1. At a point in a steel member, major principal stress is 1000 kg/cm^2, and minor principal stress is compressive. If uni-axial tensile yield stress is 1500 kg/cm^2, then magnitude of minor principal stress at which yielding will commence, according to maximum shearing stress theory is, 500 kg/cm2 (Sy/2 = (S1-S2)/2.
2. If an element is subjected to pure shearing stress T, then maximum principal stress T is equal to T.
3. A brittle material of 4 sq. cm cross section carries an axial tensile load of 20 T. What will be the maximum shear stress in the block? Ans : 2.5 T/cm^2 = 2500 kg/cm^2.
4. Given EI = (1/100)wL^3, where w is central load as well as total udl load acting on the span. What will be the deflection when a udl equal to w and a concentrated load w is acting centrally to a simply supported beam? Ans: 1300/384
2. If an element is subjected to pure shearing stress T, then maximum principal stress T is equal to T.
3. A brittle material of 4 sq. cm cross section carries an axial tensile load of 20 T. What will be the maximum shear stress in the block? Ans : 2.5 T/cm^2 = 2500 kg/cm^2.
4. Given EI = (1/100)wL^3, where w is central load as well as total udl load acting on the span. What will be the deflection when a udl equal to w and a concentrated load w is acting centrally to a simply supported beam? Ans: 1300/384
No comments:
Post a Comment